Base | Representation |
---|---|
bin | 100000100010111101100011… |
… | …100100110010010010011101 |
3 | 200202211001110220010112101021 |
4 | 200202331203210302102131 |
5 | 122230201303142130331 |
6 | 1224233343523044141 |
7 | 42102345525030001 |
oct | 4042754344622235 |
9 | 622731426115337 |
10 | 143140045661341 |
11 | 41677397139103 |
12 | 140795bb810651 |
13 | 61b40823cbc21 |
14 | 274c02d8da701 |
15 | 1183603971211 |
hex | 822f6393249d |
143140045661341 has 2 divisors, whose sum is σ = 143140045661342. Its totient is φ = 143140045661340.
The previous prime is 143140045661293. The next prime is 143140045661443. The reversal of 143140045661341 is 143166540041341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 119035824405316 + 24104221256025 = 10910354^2 + 4909605^2 .
It is a cyclic number.
It is not a de Polignac number, because 143140045661341 - 237 = 143002606707869 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (143140045667341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71570022830670 + 71570022830671.
It is an arithmetic number, because the mean of its divisors is an integer number (71570022830671).
Almost surely, 2143140045661341 is an apocalyptic number.
It is an amenable number.
143140045661341 is a deficient number, since it is larger than the sum of its proper divisors (1).
143140045661341 is an equidigital number, since it uses as much as digits as its factorization.
143140045661341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 414720, while the sum is 43.
The spelling of 143140045661341 in words is "one hundred forty-three trillion, one hundred forty billion, forty-five million, six hundred sixty-one thousand, three hundred forty-one".
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