Base | Representation |
---|---|
bin | 1101000001001011111000… |
… | …0000101000010101110111 |
3 | 1212200101222120211012010022 |
4 | 3100102332000220111313 |
5 | 3334010102312212201 |
6 | 50235434113115355 |
7 | 3005103505600115 |
oct | 320227600502567 |
9 | 55611876735108 |
10 | 14314018866551 |
11 | 46195a5536908 |
12 | 173219bb58b5b |
13 | 7caa63268c61 |
14 | 376b33398ab5 |
15 | 19c5191ba41b |
hex | d04be028577 |
14314018866551 has 24 divisors (see below), whose sum is σ = 15165457868160. Its totient is φ = 13508235988416.
The previous prime is 14314018866509. The next prime is 14314018866557. The reversal of 14314018866551 is 15566881041341.
It is not a de Polignac number, because 14314018866551 - 210 = 14314018865527 is a prime.
It is a super-2 number, since 2×143140188665512 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14314018866493 and 14314018866502.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14314018866557) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 444670565 + ... + 444702753.
It is an arithmetic number, because the mean of its divisors is an integer number (631894077840).
Almost surely, 214314018866551 is an apocalyptic number.
14314018866551 is a deficient number, since it is larger than the sum of its proper divisors (851439001609).
14314018866551 is a wasteful number, since it uses less digits than its factorization.
14314018866551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 36951 (or 36932 counting only the distinct ones).
The product of its (nonzero) digits is 2764800, while the sum is 53.
The spelling of 14314018866551 in words is "fourteen trillion, three hundred fourteen billion, eighteen million, eight hundred sixty-six thousand, five hundred fifty-one".
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