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143141113 is a prime number
BaseRepresentation
bin10001000100000…
…10100011111001
3100222100022200201
420202002203321
5243121003423
622112002201
73355452013
oct1042024371
9328308621
10143141113
1173888045
123bb30361
1323869cab
14150211b3
15c8772ad
hex88828f9

143141113 has 2 divisors, whose sum is σ = 143141114. Its totient is φ = 143141112.

The previous prime is 143141111. The next prime is 143141153. The reversal of 143141113 is 311141341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 94322944 + 48818169 = 9712^2 + 6987^2 .

It is a cyclic number.

It is not a de Polignac number, because 143141113 - 21 = 143141111 is a prime.

Together with 143141111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (143141111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71570556 + 71570557.

It is an arithmetic number, because the mean of its divisors is an integer number (71570557).

Almost surely, 2143141113 is an apocalyptic number.

It is an amenable number.

143141113 is a deficient number, since it is larger than the sum of its proper divisors (1).

143141113 is an equidigital number, since it uses as much as digits as its factorization.

143141113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 144, while the sum is 19.

The square root of 143141113 is about 11964.1595191639. The cubic root of 143141113 is about 523.1041071740.

Adding to 143141113 its reverse (311141341), we get a palindrome (454282454).

The spelling of 143141113 in words is "one hundred forty-three million, one hundred forty-one thousand, one hundred thirteen".