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143141205209983 is a prime number
BaseRepresentation
bin100000100010111110101000…
…101100000111001101111111
3200202211011110201000201002021
4200202332220230013031333
5122230211142013204413
61224234054544141011
742102416335030201
oct4042765054071577
9622734421021067
10143141205209983
1141677931726172
1214079884007767
1361b42086cc296
14274c0dd8da771
15118367066b18d
hex822fa8b0737f

143141205209983 has 2 divisors, whose sum is σ = 143141205209984. Its totient is φ = 143141205209982.

The previous prime is 143141205209903. The next prime is 143141205210077. The reversal of 143141205209983 is 389902502141341.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-143141205209983 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 143141205209983.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143141205209903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71570602604991 + 71570602604992.

It is an arithmetic number, because the mean of its divisors is an integer number (71570602604992).

Almost surely, 2143141205209983 is an apocalyptic number.

143141205209983 is a deficient number, since it is larger than the sum of its proper divisors (1).

143141205209983 is an equidigital number, since it uses as much as digits as its factorization.

143141205209983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1866240, while the sum is 52.

The spelling of 143141205209983 in words is "one hundred forty-three trillion, one hundred forty-one billion, two hundred five million, two hundred nine thousand, nine hundred eighty-three".