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14314130221 is a prime number
BaseRepresentation
bin11010101010011000…
…00100101100101101
31100221120120011020011
431111030010230231
5213303404131341
610324213253221
71014501046036
oct152514045455
940846504204
1014314130221
116085a53996
122935934211
131471716451
1499b0c7a8d
1558b9d3b81
hex355304b2d

14314130221 has 2 divisors, whose sum is σ = 14314130222. Its totient is φ = 14314130220.

The previous prime is 14314130183. The next prime is 14314130227. The reversal of 14314130221 is 12203141341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12379010121 + 1935120100 = 111261^2 + 43990^2 .

It is an emirp because it is prime and its reverse (12203141341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14314130221 - 217 = 14313999149 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14314130192 and 14314130201.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14314130227) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7157065110 + 7157065111.

It is an arithmetic number, because the mean of its divisors is an integer number (7157065111).

Almost surely, 214314130221 is an apocalyptic number.

It is an amenable number.

14314130221 is a deficient number, since it is larger than the sum of its proper divisors (1).

14314130221 is an equidigital number, since it uses as much as digits as its factorization.

14314130221 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 14314130221 its reverse (12203141341), we get a palindrome (26517271562).

The spelling of 14314130221 in words is "fourteen billion, three hundred fourteen million, one hundred thirty thousand, two hundred twenty-one".