Base | Representation |
---|---|
bin | 11010101010011000… |
… | …10110001111111011 |
3 | 1100221120200210211121 |
4 | 31111030112033323 |
5 | 213303413431412 |
6 | 10324215010111 |
7 | 1014501465442 |
oct | 152514261773 |
9 | 40846623747 |
10 | 14314202107 |
11 | 6085aa29a7 |
12 | 2935969937 |
13 | 147174009a |
14 | 99b105d59 |
15 | 58b9ea107 |
hex | 3553163fb |
14314202107 has 2 divisors, whose sum is σ = 14314202108. Its totient is φ = 14314202106.
The previous prime is 14314202033. The next prime is 14314202117. The reversal of 14314202107 is 70120241341.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14314202107 is a prime.
It is not a weakly prime, because it can be changed into another prime (14314202117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7157101053 + 7157101054.
It is an arithmetic number, because the mean of its divisors is an integer number (7157101054).
Almost surely, 214314202107 is an apocalyptic number.
14314202107 is a deficient number, since it is larger than the sum of its proper divisors (1).
14314202107 is an equidigital number, since it uses as much as digits as its factorization.
14314202107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 14314202107 its reverse (70120241341), we get a palindrome (84434443448).
The spelling of 14314202107 in words is "fourteen billion, three hundred fourteen million, two hundred two thousand, one hundred seven".
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