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143142021431 is a prime number
BaseRepresentation
bin1000010101001111101…
…1011110100100110111
3111200110210222002212022
42011103323132210313
54321123324141211
6145431502143355
713225123051433
oct2052373364467
9450423862768
10143142021431
1155784a37372
12238a9b81b5b
1310662810986
146cdca439c3
153acb9babdb
hex2153ede937

143142021431 has 2 divisors, whose sum is σ = 143142021432. Its totient is φ = 143142021430.

The previous prime is 143142021377. The next prime is 143142021461. The reversal of 143142021431 is 134120241341.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 143142021431 - 210 = 143142020407 is a prime.

It is a super-2 number, since 2×1431420214312 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 143142021431.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143142021461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71571010715 + 71571010716.

It is an arithmetic number, because the mean of its divisors is an integer number (71571010716).

Almost surely, 2143142021431 is an apocalyptic number.

143142021431 is a deficient number, since it is larger than the sum of its proper divisors (1).

143142021431 is an equidigital number, since it uses as much as digits as its factorization.

143142021431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 143142021431 its reverse (134120241341), we get a palindrome (277262262772).

The spelling of 143142021431 in words is "one hundred forty-three billion, one hundred forty-two million, twenty-one thousand, four hundred thirty-one".