Base | Representation |
---|---|
bin | 11010101010011000… |
… | …10110011111111011 |
3 | 1100221120200212020112 |
4 | 31111030112133323 |
5 | 213303414000011 |
6 | 10324215014535 |
7 | 1014501501434 |
oct | 152514263773 |
9 | 40846625215 |
10 | 14314203131 |
11 | 6085aa3748 |
12 | 293596a44b |
13 | 14717406a7 |
14 | 99b10648b |
15 | 58b9ea58b |
hex | 3553167fb |
14314203131 has 4 divisors (see below), whose sum is σ = 14386134000. Its totient is φ = 14242272264.
The previous prime is 14314203121. The next prime is 14314203139. The reversal of 14314203131 is 13130241341.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14314203131 - 210 = 14314202107 is a prime.
It is a super-2 number, since 2×143142031312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14314203097 and 14314203106.
It is not an unprimeable number, because it can be changed into a prime (14314203139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35965136 + ... + 35965533.
It is an arithmetic number, because the mean of its divisors is an integer number (3596533500).
Almost surely, 214314203131 is an apocalyptic number.
14314203131 is a deficient number, since it is larger than the sum of its proper divisors (71930869).
14314203131 is an equidigital number, since it uses as much as digits as its factorization.
14314203131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71930868.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 14314203131 its reverse (13130241341), we get a palindrome (27444444472).
The spelling of 14314203131 in words is "fourteen billion, three hundred fourteen million, two hundred three thousand, one hundred thirty-one".
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