Base | Representation |
---|---|
bin | 1101000001001101000000… |
… | …1110010010001010000111 |
3 | 1212200102202212210201001011 |
4 | 3100103100032102022013 |
5 | 3334011214023414331 |
6 | 50235524310343051 |
7 | 3005114206103005 |
oct | 320232016221207 |
9 | 55612685721034 |
10 | 14314324435591 |
11 | 4619741a74404 |
12 | 173226635aa87 |
13 | 7caab166683b |
14 | 376b61bbba75 |
15 | 19c535e293b1 |
hex | d04d0392287 |
14314324435591 has 2 divisors, whose sum is σ = 14314324435592. Its totient is φ = 14314324435590.
The previous prime is 14314324435577. The next prime is 14314324435597. The reversal of 14314324435591 is 19553442341341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14314324435591 - 25 = 14314324435559 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14314324435597) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7157162217795 + 7157162217796.
It is an arithmetic number, because the mean of its divisors is an integer number (7157162217796).
Almost surely, 214314324435591 is an apocalyptic number.
14314324435591 is a deficient number, since it is larger than the sum of its proper divisors (1).
14314324435591 is an equidigital number, since it uses as much as digits as its factorization.
14314324435591 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3110400, while the sum is 49.
The spelling of 14314324435591 in words is "fourteen trillion, three hundred fourteen billion, three hundred twenty-four million, four hundred thirty-five thousand, five hundred ninety-one".
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