Base | Representation |
---|---|
bin | 1000010101010000001… |
… | …1110010110001111101 |
3 | 111200110222001212010201 |
4 | 2011110003302301331 |
5 | 4321124403420331 |
6 | 145432021003501 |
7 | 13225150431031 |
oct | 2052403626175 |
9 | 450428055121 |
10 | 143144201341 |
11 | 55786196149 |
12 | 238aa853591 |
13 | 106630c4c6b |
14 | 6cdd0501c1 |
15 | 3acbc9ba61 |
hex | 21540f2c7d |
143144201341 has 2 divisors, whose sum is σ = 143144201342. Its totient is φ = 143144201340.
The previous prime is 143144201279. The next prime is 143144201377. The reversal of 143144201341 is 143102441341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 131028796441 + 12115404900 = 361979^2 + 110070^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-143144201341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (143144271341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71572100670 + 71572100671.
It is an arithmetic number, because the mean of its divisors is an integer number (71572100671).
Almost surely, 2143144201341 is an apocalyptic number.
It is an amenable number.
143144201341 is a deficient number, since it is larger than the sum of its proper divisors (1).
143144201341 is an equidigital number, since it uses as much as digits as its factorization.
143144201341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 143144201341 its reverse (143102441341), we get a palindrome (286246642682).
The spelling of 143144201341 in words is "one hundred forty-three billion, one hundred forty-four million, two hundred one thousand, three hundred forty-one".
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