Base | Representation |
---|---|
bin | 100000100011000001110000… |
… | …111101010100111111010000 |
3 | 200202211111010212101011021220 |
4 | 200203001300331110333100 |
5 | 122230240032140303112 |
6 | 1224235412211445040 |
7 | 42102565524134343 |
oct | 4043016075247720 |
9 | 622744125334256 |
10 | 143144565166032 |
11 | 416792a62a0951 |
12 | 1407a4612b6780 |
13 | 61b4622844561 |
14 | 274c33bc4245a |
15 | 11837ba61398c |
hex | 823070f54fd0 |
143144565166032 has 80 divisors (see below), whose sum is σ = 370577910245760. Its totient is φ = 47613306205696.
The previous prime is 143144565166019. The next prime is 143144565166061. The reversal of 143144565166032 is 230661565441341.
It is a super-3 number, since 3×1431445651660323 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 43971394 + ... + 47114462.
It is an arithmetic number, because the mean of its divisors is an integer number (4632223878072).
Almost surely, 2143144565166032 is an apocalyptic number.
143144565166032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
143144565166032 is an abundant number, since it is smaller than the sum of its proper divisors (227433345079728).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
143144565166032 is a wasteful number, since it uses less digits than its factorization.
143144565166032 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3145100 (or 3145094 counting only the distinct ones).
The product of its (nonzero) digits is 6220800, while the sum is 51.
The spelling of 143144565166032 in words is "one hundred forty-three trillion, one hundred forty-four billion, five hundred sixty-five million, one hundred sixty-six thousand, thirty-two".
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