Base | Representation |
---|---|
bin | 11010101010011011… |
… | …10100010010000111 |
3 | 1100221121102101011221 |
4 | 31111031310102013 |
5 | 213304013243041 |
6 | 10324231141211 |
7 | 1014504661405 |
oct | 152515642207 |
9 | 40847371157 |
10 | 14314587271 |
11 | 6086236316 |
12 | 2935b14807 |
13 | 14718464aa |
14 | 99b1a6475 |
15 | 58ba742d1 |
hex | 355374487 |
14314587271 has 2 divisors, whose sum is σ = 14314587272. Its totient is φ = 14314587270.
The previous prime is 14314587247. The next prime is 14314587293. The reversal of 14314587271 is 17278541341.
14314587271 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (17278541341) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14314587271 - 25 = 14314587239 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14314588271) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7157293635 + 7157293636.
It is an arithmetic number, because the mean of its divisors is an integer number (7157293636).
Almost surely, 214314587271 is an apocalyptic number.
14314587271 is a deficient number, since it is larger than the sum of its proper divisors (1).
14314587271 is an equidigital number, since it uses as much as digits as its factorization.
14314587271 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 188160, while the sum is 43.
The spelling of 14314587271 in words is "fourteen billion, three hundred fourteen million, five hundred eighty-seven thousand, two hundred seventy-one".
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