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1431522042323 is a prime number
BaseRepresentation
bin10100110101001101010…
…111001110000111010011
312001212000020021110101212
4110311031113032013103
5141423224120323243
63013344313250335
7205265310410042
oct24651527160723
95055006243355
101431522042323
1150211796723a
121b1531a039ab
13a4cb840b119
144d400c54559
15273856d9318
hex14d4d5ce1d3

1431522042323 has 2 divisors, whose sum is σ = 1431522042324. Its totient is φ = 1431522042322.

The previous prime is 1431522042311. The next prime is 1431522042383. The reversal of 1431522042323 is 3232402251341.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1431522042323 - 238 = 1156644135379 is a prime.

It is a super-3 number, since 3×14315220423233 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 1431522042323.

It is not a weakly prime, because it can be changed into another prime (1431522042383) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715761021161 + 715761021162.

It is an arithmetic number, because the mean of its divisors is an integer number (715761021162).

Almost surely, 21431522042323 is an apocalyptic number.

1431522042323 is a deficient number, since it is larger than the sum of its proper divisors (1).

1431522042323 is an equidigital number, since it uses as much as digits as its factorization.

1431522042323 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34560, while the sum is 32.

Adding to 1431522042323 its reverse (3232402251341), we get a palindrome (4663924293664).

The spelling of 1431522042323 in words is "one trillion, four hundred thirty-one billion, five hundred twenty-two million, forty-two thousand, three hundred twenty-three".