Base | Representation |
---|---|
bin | 10100110101001101111… |
… | …110001011001101100111 |
3 | 12001212000221111021021011 |
4 | 110311031332023031213 |
5 | 141423234224112210 |
6 | 3013345320203051 |
7 | 205265463250621 |
oct | 24651576131547 |
9 | 5055027437234 |
10 | 1431532254055 |
11 | 502122701492 |
12 | 1b1535309487 |
13 | a4cba575177 |
14 | 4d402351c11 |
15 | 27386554d8a |
hex | 14d4df8b367 |
1431532254055 has 64 divisors (see below), whose sum is σ = 1929833164800. Its totient is φ = 1014214417920.
The previous prime is 1431532254041. The next prime is 1431532254059. The reversal of 1431532254055 is 5504522351341.
It is not a de Polignac number, because 1431532254055 - 217 = 1431532122983 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1431532253999 and 1431532254017.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1431532254059) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 72800925 + ... + 72820585.
It is an arithmetic number, because the mean of its divisors is an integer number (30153643200).
Almost surely, 21431532254055 is an apocalyptic number.
1431532254055 is a deficient number, since it is larger than the sum of its proper divisors (498300910745).
1431532254055 is a wasteful number, since it uses less digits than its factorization.
1431532254055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20464.
The product of its (nonzero) digits is 360000, while the sum is 40.
The spelling of 1431532254055 in words is "one trillion, four hundred thirty-one billion, five hundred thirty-two million, two hundred fifty-four thousand, fifty-five".
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