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1431540113 is a prime number
BaseRepresentation
bin101010101010011…
…1001000110010001
310200202200202212012
41111110321012101
510412433240423
6354014512305
750321614223
oct12524710621
93622622765
101431540113
11675081303
1233b505695
1319a772773
14d81a2413
1585a25078
hex55539191

1431540113 has 2 divisors, whose sum is σ = 1431540114. Its totient is φ = 1431540112.

The previous prime is 1431540107. The next prime is 1431540139. The reversal of 1431540113 is 3110451341.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1328456704 + 103083409 = 36448^2 + 10153^2 .

It is an emirp because it is prime and its reverse (3110451341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1431540113 - 230 = 357798289 is a prime.

It is not a weakly prime, because it can be changed into another prime (1431540163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715770056 + 715770057.

It is an arithmetic number, because the mean of its divisors is an integer number (715770057).

Almost surely, 21431540113 is an apocalyptic number.

It is an amenable number.

1431540113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1431540113 is an equidigital number, since it uses as much as digits as its factorization.

1431540113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 23.

The square root of 1431540113 is about 37835.6989231070. The cubic root of 1431540113 is about 1127.0274847269.

Adding to 1431540113 its reverse (3110451341), we get a palindrome (4541991454).

The spelling of 1431540113 in words is "one billion, four hundred thirty-one million, five hundred forty thousand, one hundred thirteen".