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143160602123113 is a prime number
BaseRepresentation
bin100000100011010000101100…
…110101011101101101101001
3200202220000112111201222200021
4200203100230311131231221
5122231020403120414423
61224251023411240441
742104004115050301
oct4043205465355551
9622800474658607
10143160602123113
1141685085789093
1214081597ba9121
1361b5caa16a283
14274d01da74601
151183e084a995d
hex82342cd5db69

143160602123113 has 2 divisors, whose sum is σ = 143160602123114. Its totient is φ = 143160602123112.

The previous prime is 143160602123101. The next prime is 143160602123159. The reversal of 143160602123113 is 311321206061341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 121790581159129 + 21370020963984 = 11035877^2 + 4622772^2 .

It is a cyclic number.

It is not a de Polignac number, because 143160602123113 - 225 = 143160568568681 is a prime.

It is not a weakly prime, because it can be changed into another prime (143160602123173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71580301061556 + 71580301061557.

It is an arithmetic number, because the mean of its divisors is an integer number (71580301061557).

Almost surely, 2143160602123113 is an apocalyptic number.

It is an amenable number.

143160602123113 is a deficient number, since it is larger than the sum of its proper divisors (1).

143160602123113 is an equidigital number, since it uses as much as digits as its factorization.

143160602123113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 34.

Adding to 143160602123113 its reverse (311321206061341), we get a palindrome (454481808184454).

The spelling of 143160602123113 in words is "one hundred forty-three trillion, one hundred sixty billion, six hundred two million, one hundred twenty-three thousand, one hundred thirteen".