Base | Representation |
---|---|
bin | 10100110101011010011… |
… | …010100011110010000101 |
3 | 12001212120111022202002222 |
4 | 110311122122203302011 |
5 | 141424201200140232 |
6 | 3013422134542125 |
7 | 205303606611545 |
oct | 24653232436205 |
9 | 5055514282088 |
10 | 1431741021317 |
11 | 50221a532412 |
12 | 1b1593207945 |
13 | a50218abba9 |
14 | 4d421d77325 |
15 | 27399a41d12 |
hex | 14d5a6a3c85 |
1431741021317 has 2 divisors, whose sum is σ = 1431741021318. Its totient is φ = 1431741021316.
The previous prime is 1431741021259. The next prime is 1431741021349. The reversal of 1431741021317 is 7131201471341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1221469250401 + 210271770916 = 1105201^2 + 458554^2 .
It is a cyclic number.
It is not a de Polignac number, because 1431741021317 - 216 = 1431740955781 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1431741021617) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715870510658 + 715870510659.
It is an arithmetic number, because the mean of its divisors is an integer number (715870510659).
Almost surely, 21431741021317 is an apocalyptic number.
It is an amenable number.
1431741021317 is a deficient number, since it is larger than the sum of its proper divisors (1).
1431741021317 is an equidigital number, since it uses as much as digits as its factorization.
1431741021317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14112, while the sum is 35.
Adding to 1431741021317 its reverse (7131201471341), we get a palindrome (8562942492658).
The spelling of 1431741021317 in words is "one trillion, four hundred thirty-one billion, seven hundred forty-one million, twenty-one thousand, three hundred seventeen".
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