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14320142300030 = 2572397167739743
BaseRepresentation
bin1101000001100010101011…
…1111101011001101111110
31212200222210100010211200212
43100120222333223031332
53334110122412100110
650242325455352422
73005411322116630
oct320305277531576
955628710124625
1014320142300030
114621158004036
12173340a822712
137cb4caa91688
14377154738a50
1519c776a85e05
hexd062afeb37e

14320142300030 has 256 divisors, whose sum is σ = 31326634967040. Its totient is φ = 4607586643968.

The previous prime is 14320142299999. The next prime is 14320142300119. The reversal of 14320142300030 is 3000324102341.

It is a super-3 number, since 3×143201423000303 (a number of 40 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (23).

It is a junction number, because it is equal to n+sod(n) for n = 14320142299969 and 14320142300005.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 19273407839 + ... + 19273408581.

It is an arithmetic number, because the mean of its divisors is an integer number (122369667840).

Almost surely, 214320142300030 is an apocalyptic number.

14320142300030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

14320142300030 is an abundant number, since it is smaller than the sum of its proper divisors (17006492667010).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14320142300030 is a wasteful number, since it uses less digits than its factorization.

14320142300030 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1783.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 14320142300030 its reverse (3000324102341), we get a palindrome (17320466402371).

The spelling of 14320142300030 in words is "fourteen trillion, three hundred twenty billion, one hundred forty-two million, three hundred thousand, thirty".