Base | Representation |
---|---|
bin | 1101000001100011010110… |
… | …1010101010011001011011 |
3 | 1212201000020211001001202121 |
4 | 3100120311222222121123 |
5 | 3334111004230403034 |
6 | 50242355333042111 |
7 | 3005415625002211 |
oct | 320306552523133 |
9 | 55630224031677 |
10 | 14320321341019 |
11 | 462123a0811a1 |
12 | 173345a786337 |
13 | 7cb528bbaba5 |
14 | 377170422cb1 |
15 | 19c7876501b4 |
hex | d0635aaa65b |
14320321341019 has 2 divisors, whose sum is σ = 14320321341020. Its totient is φ = 14320321341018.
The previous prime is 14320321340993. The next prime is 14320321341031. The reversal of 14320321341019 is 91014312302341.
14320321341019 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14320321341019 - 27 = 14320321340891 is a prime.
It is a super-2 number, since 2×143203213410192 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14320321341119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7160160670509 + 7160160670510.
It is an arithmetic number, because the mean of its divisors is an integer number (7160160670510).
Almost surely, 214320321341019 is an apocalyptic number.
14320321341019 is a deficient number, since it is larger than the sum of its proper divisors (1).
14320321341019 is an equidigital number, since it uses as much as digits as its factorization.
14320321341019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 34.
The spelling of 14320321341019 in words is "fourteen trillion, three hundred twenty billion, three hundred twenty-one million, three hundred forty-one thousand, nineteen".
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