Base | Representation |
---|---|
bin | 1101000001100011110100… |
… | …0000011000000100100110 |
3 | 1212201000120101201211221222 |
4 | 3100120331000120010212 |
5 | 3334111232241124023 |
6 | 50242415452140342 |
7 | 3005421651421352 |
oct | 320307500300446 |
9 | 55630511654858 |
10 | 14320444473638 |
11 | 46212a2632596 |
12 | 1733493a676b2 |
13 | 7cb548570924 |
14 | 377182916462 |
15 | 19c793373cc8 |
hex | d063d018126 |
14320444473638 has 8 divisors (see below), whose sum is σ = 21739469924088. Its totient is φ = 7073954498944.
The previous prime is 14320444473631. The next prime is 14320444473677. The reversal of 14320444473638 is 83637444402341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a self number, because there is not a number n which added to its sum of digits gives 14320444473638.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14320444473631) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43133868731 + ... + 43133869062.
It is an arithmetic number, because the mean of its divisors is an integer number (2717433740511).
Almost surely, 214320444473638 is an apocalyptic number.
14320444473638 is a deficient number, since it is larger than the sum of its proper divisors (7419025450450).
14320444473638 is an equidigital number, since it uses as much as digits as its factorization.
14320444473638 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 86267737878.
The product of its (nonzero) digits is 18579456, while the sum is 53.
Adding to 14320444473638 its reverse (83637444402341), we get a palindrome (97957888875979).
The spelling of 14320444473638 in words is "fourteen trillion, three hundred twenty billion, four hundred forty-four million, four hundred seventy-three thousand, six hundred thirty-eight".
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