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14321013103 is a prime number
BaseRepresentation
bin11010101011001100…
…10101000101101111
31100222001111211202201
431111212111011233
5213312134404403
610325021002331
71014613413535
oct152546250557
940861454681
1014321013103
116089925121
1229380b33a7
131472c86267
1499bd9a155
1558c3e321d
hex35599516f

14321013103 has 2 divisors, whose sum is σ = 14321013104. Its totient is φ = 14321013102.

The previous prime is 14321013037. The next prime is 14321013137. The reversal of 14321013103 is 30131012341.

It is a strong prime.

It is an emirp because it is prime and its reverse (30131012341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14321013103 - 213 = 14321004911 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14321913103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7160506551 + 7160506552.

It is an arithmetic number, because the mean of its divisors is an integer number (7160506552).

Almost surely, 214321013103 is an apocalyptic number.

14321013103 is a deficient number, since it is larger than the sum of its proper divisors (1).

14321013103 is an equidigital number, since it uses as much as digits as its factorization.

14321013103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 14321013103 its reverse (30131012341), we get a palindrome (44452025444).

It can be divided in two parts, 1432101 and 3103, that added together give a square (1435204 = 11982).

The spelling of 14321013103 in words is "fourteen billion, three hundred twenty-one million, thirteen thousand, one hundred three".