14321231403131 has 2 divisors, whose sum is σ = 14321231403132. Its totient is φ = 14321231403130.

The previous prime is 14321231403041. The next prime is 14321231403133. The reversal of 14321231403131 is 13130413212341.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14321231403131 - 2²⁶ = 14321164294267 is a prime.

It is a super-2 number, since 2×14321231403131² (a number of 27 digits) contains 22 as substring.

Together with 14321231403133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14321231403094 and 14321231403103.

It is not a weakly prime, because it can be changed into another prime (14321231403133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7160615701565 + 7160615701566.

It is an arithmetic number, because the mean of its divisors is an integer number (7160615701566).

Almost surely, 2^{14321231403131} is an apocalyptic number.

14321231403131 is a deficient number, since it is larger than the sum of its proper divisors (1).

14321231403131 is an equidigital number, since it uses as much as digits as its factorization.

14321231403131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 14321231403131 its reverse (13130413212341), we get a palindrome (27451644615472).

The spelling of 14321231403131 in words is "fourteen trillion, three hundred twenty-one billion, two hundred thirty-one million, four hundred three thousand, one hundred thirty-one".