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14322112432 = 24895132027
BaseRepresentation
bin11010101011010101…
…00001011110110000
31100222010120200202121
431111222201132300
5213312430044212
610325100324024
71014625642555
oct152552413660
940863520677
1014322112432
11608a506061
122938543614
13147327c754
1499c1a4a2c
1558c55dd07
hex355aa17b0

14322112432 has 10 divisors (see below), whose sum is σ = 27749092868. Its totient is φ = 7161056208.

The previous prime is 14322112411. The next prime is 14322112439. The reversal of 14322112432 is 23421122341.

14322112432 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 14322112397 and 14322112406.

It is not an unprimeable number, because it can be changed into a prime (14322112439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 447565998 + ... + 447566029.

Almost surely, 214322112432 is an apocalyptic number.

It is an amenable number.

14322112432 is a deficient number, since it is larger than the sum of its proper divisors (13426980436).

14322112432 is an equidigital number, since it uses as much as digits as its factorization.

14322112432 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 895132035 (or 895132029 counting only the distinct ones).

The product of its digits is 2304, while the sum is 25.

Adding to 14322112432 its reverse (23421122341), we get a palindrome (37743234773).

Subtracting 14322112432 from its reverse (23421122341), we obtain a palindrome (9099009909).

The spelling of 14322112432 in words is "fourteen billion, three hundred twenty-two million, one hundred twelve thousand, four hundred thirty-two".

Divisors: 1 2 4 8 16 895132027 1790264054 3580528108 7161056216 14322112432