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1432220301241 is a prime number
BaseRepresentation
bin10100110101110110111…
…110110111011110111001
312001220210220011200120021
4110311312332313132321
5141431141344114431
63013541455330441
7205321516460242
oct24656676673671
95056726150507
101432220301241
11502446027524
121b16a7820a21
13a5099c8ab92
144d469897cc9
15273c6b65b11
hex14d76fb77b9

1432220301241 has 2 divisors, whose sum is σ = 1432220301242. Its totient is φ = 1432220301240.

The previous prime is 1432220301233. The next prime is 1432220301247. The reversal of 1432220301241 is 1421030222341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1320881295616 + 111339005625 = 1149296^2 + 333675^2 .

It is a cyclic number.

It is not a de Polignac number, because 1432220301241 - 23 = 1432220301233 is a prime.

It is a super-2 number, since 2×14322203012412 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1432220301247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 716110150620 + 716110150621.

It is an arithmetic number, because the mean of its divisors is an integer number (716110150621).

Almost surely, 21432220301241 is an apocalyptic number.

It is an amenable number.

1432220301241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1432220301241 is an equidigital number, since it uses as much as digits as its factorization.

1432220301241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1432220301241 its reverse (1421030222341), we get a palindrome (2853250523582).

The spelling of 1432220301241 in words is "one trillion, four hundred thirty-two billion, two hundred twenty million, three hundred one thousand, two hundred forty-one".