Base | Representation |
---|---|
bin | 100000100100001100110001… |
… | …111111001000010001010011 |
3 | 200210010012001101102201212202 |
4 | 200210030301333020101103 |
5 | 122233100012420132433 |
6 | 1224340413020313415 |
7 | 42111446550645005 |
oct | 4044146177102123 |
9 | 623105041381782 |
10 | 143225113052243 |
11 | 416aa47a4a0a52 |
12 | 14091ba06a286b |
13 | 61bc0bb3296a1 |
14 | 27521bd67a375 |
15 | 1185931c58ee8 |
hex | 824331fc8453 |
143225113052243 has 2 divisors, whose sum is σ = 143225113052244. Its totient is φ = 143225113052242.
The previous prime is 143225113052191. The next prime is 143225113052251. The reversal of 143225113052243 is 342250311522341.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-143225113052243 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 143225113052197 and 143225113052206.
It is not a weakly prime, because it can be changed into another prime (143225113052293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71612556526121 + 71612556526122.
It is an arithmetic number, because the mean of its divisors is an integer number (71612556526122).
Almost surely, 2143225113052243 is an apocalyptic number.
143225113052243 is a deficient number, since it is larger than the sum of its proper divisors (1).
143225113052243 is an equidigital number, since it uses as much as digits as its factorization.
143225113052243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 172800, while the sum is 38.
Adding to 143225113052243 its reverse (342250311522341), we get a palindrome (485475424574584).
The spelling of 143225113052243 in words is "one hundred forty-three trillion, two hundred twenty-five billion, one hundred thirteen million, fifty-two thousand, two hundred forty-three".
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