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143231301023 is a prime number
BaseRepresentation
bin1000010101100101000…
…0000011010110011111
3111200201000221222102212
42011121100003112133
54321314203113043
6145444411511035
713230255653666
oct2053120032637
9450630858385
10143231301023
1155820376458
1223913a5847b
131067816ca35
146d0a843ddd
153ad4754018
hex215940359f

143231301023 has 2 divisors, whose sum is σ = 143231301024. Its totient is φ = 143231301022.

The previous prime is 143231301001. The next prime is 143231301043. The reversal of 143231301023 is 320103132341.

It is a strong prime.

It is an emirp because it is prime and its reverse (320103132341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 143231301023 - 28 = 143231300767 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 143231301023.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143231301043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71615650511 + 71615650512.

It is an arithmetic number, because the mean of its divisors is an integer number (71615650512).

Almost surely, 2143231301023 is an apocalyptic number.

143231301023 is a deficient number, since it is larger than the sum of its proper divisors (1).

143231301023 is an equidigital number, since it uses as much as digits as its factorization.

143231301023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 143231301023 its reverse (320103132341), we get a palindrome (463334433364).

The spelling of 143231301023 in words is "one hundred forty-three billion, two hundred thirty-one million, three hundred one thousand, twenty-three".