143232202232341 has 4 divisors (see below), whose sum is σ = 143243366965900. Its totient is φ = 143221037498784.

The previous prime is 143232202232221. The next prime is 143232202232389.

It is a happy number.

143232202232341 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 61520021640900 + 81712180591441 = 7843470^2 + 9039479^2 .

It is a cyclic number.

It is not a de Polignac number, because 143232202232341 - 2²⁷ = 143232068014613 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 143232202232297 and 143232202232306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143232202232941) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5582347536 + ... + 5582373193.

It is an arithmetic number, because the mean of its divisors is an integer number (35810841741475).

Almost surely, 2^{143232202232341} is an apocalyptic number.

It is an amenable number.

143232202232341 is a deficient number, since it is larger than the sum of its proper divisors (11164733559).

143232202232341 is a wasteful number, since it uses less digits than its factorization.

143232202232341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11164733558.

The product of its (nonzero) digits is 82944, while the sum is 34.

It can be divided in two parts, 14323220 and 2232341, that added together give a palindrome (16555561).

The spelling of 143232202232341 in words is "one hundred forty-three trillion, two hundred thirty-two billion, two hundred two million, two hundred thirty-two thousand, three hundred forty-one".