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14323240021201 is a prime number
BaseRepresentation
bin1101000001101110001110…
…1000100010110011010001
31212201021210020001101021121
43100123203220202303101
53334132443421134301
650244001114322241
73005551145243656
oct320334350426321
955637706041247
1014323240021201
1146224a7649881
121733b34129381
137cb8a279c397
14377369cdbc2d
1519c8a89ce3a1
hexd06e3a22cd1

14323240021201 has 2 divisors, whose sum is σ = 14323240021202. Its totient is φ = 14323240021200.

The previous prime is 14323240021171. The next prime is 14323240021217. The reversal of 14323240021201 is 10212004232341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10809471026176 + 3513768995025 = 3287776^2 + 1874505^2 .

It is an emirp because it is prime and its reverse (10212004232341) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14323240021201 is a prime.

It is not a weakly prime, because it can be changed into another prime (14323240001201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7161620010600 + 7161620010601.

It is an arithmetic number, because the mean of its divisors is an integer number (7161620010601).

Almost surely, 214323240021201 is an apocalyptic number.

It is an amenable number.

14323240021201 is a deficient number, since it is larger than the sum of its proper divisors (1).

14323240021201 is an equidigital number, since it uses as much as digits as its factorization.

14323240021201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 14323240021201 its reverse (10212004232341), we get a palindrome (24535244253542).

The spelling of 14323240021201 in words is "fourteen trillion, three hundred twenty-three billion, two hundred forty million, twenty-one thousand, two hundred one".