Base | Representation |
---|---|
bin | 11010101011011110… |
… | …00101111010011001 |
3 | 1100222012211112211121 |
4 | 31111233011322121 |
5 | 213313231411413 |
6 | 10325142125241 |
7 | 1014642061651 |
oct | 152557057231 |
9 | 40865745747 |
10 | 14323310233 |
11 | 6090153a81 |
12 | 2938a20821 |
13 | 14735ab9cb |
14 | 99c3d7361 |
15 | 58c6e8b8d |
hex | 355bc5e99 |
14323310233 has 2 divisors, whose sum is σ = 14323310234. Its totient is φ = 14323310232.
The previous prime is 14323310201. The next prime is 14323310311. The reversal of 14323310233 is 33201332341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14322584329 + 725904 = 119677^2 + 852^2 .
It is a cyclic number.
It is not a de Polignac number, because 14323310233 - 25 = 14323310201 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14323310198 and 14323310207.
It is not a weakly prime, because it can be changed into another prime (14323310333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7161655116 + 7161655117.
It is an arithmetic number, because the mean of its divisors is an integer number (7161655117).
Almost surely, 214323310233 is an apocalyptic number.
It is an amenable number.
14323310233 is a deficient number, since it is larger than the sum of its proper divisors (1).
14323310233 is an equidigital number, since it uses as much as digits as its factorization.
14323310233 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 14323310233 its reverse (33201332341), we get a palindrome (47524642574).
The spelling of 14323310233 in words is "fourteen billion, three hundred twenty-three million, three hundred ten thousand, two hundred thirty-three".
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