Base | Representation |
---|---|
bin | 1101000001101110111110… |
… | …0111111110101110000001 |
3 | 1212201022022020121022201021 |
4 | 3100123233213332232001 |
5 | 3334133401421400001 |
6 | 50244033102305441 |
7 | 3005556140241043 |
oct | 320335747765601 |
9 | 55638266538637 |
10 | 14323441200001 |
11 | 46225a016744a |
12 | 1733b8b588281 |
13 | 7cb90537a0ab |
14 | 377388909a93 |
15 | 19c8bb4bcba1 |
hex | d06ef9feb81 |
14323441200001 has 2 divisors, whose sum is σ = 14323441200002. Its totient is φ = 14323441200000.
The previous prime is 14323441199981. The next prime is 14323441200007. The reversal of 14323441200001 is 10000214432341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11054128800625 + 3269312399376 = 3324775^2 + 1808124^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14323441200001 is a prime.
It is not a weakly prime, because it can be changed into another prime (14323441200007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7161720600000 + 7161720600001.
It is an arithmetic number, because the mean of its divisors is an integer number (7161720600001).
Almost surely, 214323441200001 is an apocalyptic number.
It is an amenable number.
14323441200001 is a deficient number, since it is larger than the sum of its proper divisors (1).
14323441200001 is an equidigital number, since it uses as much as digits as its factorization.
14323441200001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 14323441200001 its reverse (10000214432341), we get a palindrome (24323655632342).
The spelling of 14323441200001 in words is "fourteen trillion, three hundred twenty-three billion, four hundred forty-one million, two hundred thousand, one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.060 sec. • engine limits •