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14323441203121 is a prime number
BaseRepresentation
bin1101000001101110111110…
…0111111111011110110001
31212201022022020121110222211
43100123233213333132301
53334133401421444441
650244033102332121
73005556140253121
oct320335747773661
955638266543884
1014323441203121
1146225a0169826
121733b8b58a041
137cb90537b63b
1437738890ac81
1519c8bb4bda81
hexd06ef9ff7b1

14323441203121 has 2 divisors, whose sum is σ = 14323441203122. Its totient is φ = 14323441203120.

The previous prime is 14323441202957. The next prime is 14323441203157. The reversal of 14323441203121 is 12130214432341.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14269506250000 + 53934953121 = 3777500^2 + 232239^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14323441203121 is a prime.

It is not a weakly prime, because it can be changed into another prime (14323441273121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7161720601560 + 7161720601561.

It is an arithmetic number, because the mean of its divisors is an integer number (7161720601561).

Almost surely, 214323441203121 is an apocalyptic number.

It is an amenable number.

14323441203121 is a deficient number, since it is larger than the sum of its proper divisors (1).

14323441203121 is an equidigital number, since it uses as much as digits as its factorization.

14323441203121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 14323441203121 its reverse (12130214432341), we get a palindrome (26453655635462).

The spelling of 14323441203121 in words is "fourteen trillion, three hundred twenty-three billion, four hundred forty-one million, two hundred three thousand, one hundred twenty-one".