Base | Representation |
---|---|
bin | 10100110101111110011… |
… | …000010011011110100111 |
3 | 12001221010112201001210211 |
4 | 110311332120103132213 |
5 | 141431420132110043 |
6 | 3014002051400251 |
7 | 205324554413362 |
oct | 24657630233647 |
9 | 5057115631724 |
10 | 1432344410023 |
11 | 5024aa09526a |
12 | 1b17212b3087 |
13 | a50b98c3027 |
14 | 4d47c1630d9 |
15 | 273d29cda9d |
hex | 14d7e6137a7 |
1432344410023 has 2 divisors, whose sum is σ = 1432344410024. Its totient is φ = 1432344410022.
The previous prime is 1432344409957. The next prime is 1432344410051. The reversal of 1432344410023 is 3200144432341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1432344410023 - 221 = 1432342312871 is a prime.
It is a super-2 number, since 2×14323444100232 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1432344410053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 716172205011 + 716172205012.
It is an arithmetic number, because the mean of its divisors is an integer number (716172205012).
Almost surely, 21432344410023 is an apocalyptic number.
1432344410023 is a deficient number, since it is larger than the sum of its proper divisors (1).
1432344410023 is an equidigital number, since it uses as much as digits as its factorization.
1432344410023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 1432344410023 its reverse (3200144432341), we get a palindrome (4632488842364).
The spelling of 1432344410023 in words is "one trillion, four hundred thirty-two billion, three hundred forty-four million, four hundred ten thousand, twenty-three".
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