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14323532543893 is a prime number
BaseRepresentation
bin1101000001101111010100…
…0100011011011110010101
31212201022112121111001222101
43100123311010123132111
53334134043312401033
650244050124202101
73005561326531546
oct320336504333625
955638477431871
1014323532543893
114622637786471
121733bb6099331
137cb91b27c931
14377396ac64cd
1519c8c451297d
hexd06f511b795

14323532543893 has 2 divisors, whose sum is σ = 14323532543894. Its totient is φ = 14323532543892.

The previous prime is 14323532543861. The next prime is 14323532543911. The reversal of 14323532543893 is 39834523532341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12357320028804 + 1966212515089 = 3515298^2 + 1402217^2 .

It is a cyclic number.

It is not a de Polignac number, because 14323532543893 - 25 = 14323532543861 is a prime.

It is a super-3 number, since 3×143235325438933 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14323532553893) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7161766271946 + 7161766271947.

It is an arithmetic number, because the mean of its divisors is an integer number (7161766271947).

Almost surely, 214323532543893 is an apocalyptic number.

It is an amenable number.

14323532543893 is a deficient number, since it is larger than the sum of its proper divisors (1).

14323532543893 is an equidigital number, since it uses as much as digits as its factorization.

14323532543893 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 27993600, while the sum is 55.

The spelling of 14323532543893 in words is "fourteen trillion, three hundred twenty-three billion, five hundred thirty-two million, five hundred forty-three thousand, eight hundred ninety-three".