Base | Representation |
---|---|
bin | 11010101011100011… |
… | …10110011001101011 |
3 | 1100222021012021110121 |
4 | 31111301312121223 |
5 | 213313423030011 |
6 | 10325205424111 |
7 | 1014651162352 |
oct | 152561663153 |
9 | 40867167417 |
10 | 14324033131 |
11 | 60905a8111 |
12 | 293910b037 |
13 | 14737a2a65 |
14 | 99c544999 |
15 | 58c7dce71 |
hex | 355c7666b |
14324033131 has 2 divisors, whose sum is σ = 14324033132. Its totient is φ = 14324033130.
The previous prime is 14324033123. The next prime is 14324033153. The reversal of 14324033131 is 13133042341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14324033131 - 23 = 14324033123 is a prime.
It is a super-2 number, since 2×143240331312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14324033096 and 14324033105.
It is not a weakly prime, because it can be changed into another prime (14324033431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7162016565 + 7162016566.
It is an arithmetic number, because the mean of its divisors is an integer number (7162016566).
Almost surely, 214324033131 is an apocalyptic number.
14324033131 is a deficient number, since it is larger than the sum of its proper divisors (1).
14324033131 is an equidigital number, since it uses as much as digits as its factorization.
14324033131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 14324033131 its reverse (13133042341), we get a palindrome (27457075472).
The spelling of 14324033131 in words is "fourteen billion, three hundred twenty-four million, thirty-three thousand, one hundred thirty-one".
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