Base | Representation |
---|---|
bin | 1101000001110010000100… |
… | …1001001110110010001011 |
3 | 1212201101110010220100020202 |
4 | 3100130201021032302023 |
5 | 3334142102113001024 |
6 | 50244251341242415 |
7 | 3005615546024633 |
oct | 320344111166213 |
9 | 55641403810222 |
10 | 14324272000139 |
11 | 4622987124932 |
12 | 173418186340b |
13 | 7cba085251ca |
14 | 377426db16c3 |
15 | 19c9193cabae |
hex | d072124ec8b |
14324272000139 has 2 divisors, whose sum is σ = 14324272000140. Its totient is φ = 14324272000138.
The previous prime is 14324272000133. The next prime is 14324272000153. The reversal of 14324272000139 is 93100027242341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14324272000139 - 220 = 14324270951563 is a prime.
It is a super-3 number, since 3×143242720001393 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (14324272000133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7162136000069 + 7162136000070.
It is an arithmetic number, because the mean of its divisors is an integer number (7162136000070).
Almost surely, 214324272000139 is an apocalyptic number.
14324272000139 is a deficient number, since it is larger than the sum of its proper divisors (1).
14324272000139 is an equidigital number, since it uses as much as digits as its factorization.
14324272000139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72576, while the sum is 38.
The spelling of 14324272000139 in words is "fourteen trillion, three hundred twenty-four billion, two hundred seventy-two million, one hundred thirty-nine", and thus it is an aban number.
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