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143243453239 is a prime number
BaseRepresentation
bin1000010101100111111…
…0011010001100110111
3111200201212211101010221
42011121332122030313
54321330311000424
6145445524155211
713230464156125
oct2053176321467
9450655741127
10143243453239
1155827216607
1223917b38b07
131067a8360b3
146d0c2c8915
153ad58549e4
hex2159f9a337

143243453239 has 2 divisors, whose sum is σ = 143243453240. Its totient is φ = 143243453238.

The previous prime is 143243453203. The next prime is 143243453293. The reversal of 143243453239 is 932354342341.

Together with next prime (143243453293) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is an emirp because it is prime and its reverse (932354342341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 143243453239 - 225 = 143209898807 is a prime.

It is a super-2 number, since 2×1432434532392 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 143243453195 and 143243453204.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143243153239) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71621726619 + 71621726620.

It is an arithmetic number, because the mean of its divisors is an integer number (71621726620).

Almost surely, 2143243453239 is an apocalyptic number.

143243453239 is a deficient number, since it is larger than the sum of its proper divisors (1).

143243453239 is an equidigital number, since it uses as much as digits as its factorization.

143243453239 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 933120, while the sum is 43.

The spelling of 143243453239 in words is "one hundred forty-three billion, two hundred forty-three million, four hundred fifty-three thousand, two hundred thirty-nine".