14324403312451 has 2 divisors, whose sum is σ = 14324403312452. Its totient is φ = 14324403312450.

The previous prime is 14324403312433. The next prime is 14324403312487. The reversal of 14324403312451 is 15421330442341.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14324403312451 is a prime.

It is a super-2 number, since 2×14324403312451² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14324403312451.

It is not a weakly prime, because it can be changed into another prime (14324403319451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7162201656225 + 7162201656226.

It is an arithmetic number, because the mean of its divisors is an integer number (7162201656226).

Almost surely, 2^{14324403312451} is an apocalyptic number.

14324403312451 is a deficient number, since it is larger than the sum of its proper divisors (1).

14324403312451 is an equidigital number, since it uses as much as digits as its factorization.

14324403312451 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 138240, while the sum is 37.

Adding to 14324403312451 its reverse (15421330442341), we get a palindrome (29745733754792).

The spelling of 14324403312451 in words is "fourteen trillion, three hundred twenty-four billion, four hundred three million, three hundred twelve thousand, four hundred fifty-one".