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14324403312487 is a prime number
BaseRepresentation
bin1101000001110010100011…
…1110001001011101100111
31212201101210021222200221001
43100130220332021131213
53334142334221444422
650244312351534131
73005622032122522
oct320345076113547
955641707880831
1014324403312487
114622a44262834
1217341b982a347
137cba297b0118
1437743a5d3bb9
1519c925bb8227
hexd0728f89767

14324403312487 has 2 divisors, whose sum is σ = 14324403312488. Its totient is φ = 14324403312486.

The previous prime is 14324403312451. The next prime is 14324403312493. The reversal of 14324403312487 is 78421330442341.

It is a strong prime.

It is an emirp because it is prime and its reverse (78421330442341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14324403312487 - 211 = 14324403310439 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14324403312497) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7162201656243 + 7162201656244.

It is an arithmetic number, because the mean of its divisors is an integer number (7162201656244).

Almost surely, 214324403312487 is an apocalyptic number.

14324403312487 is a deficient number, since it is larger than the sum of its proper divisors (1).

14324403312487 is an equidigital number, since it uses as much as digits as its factorization.

14324403312487 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1548288, while the sum is 46.

The spelling of 14324403312487 in words is "fourteen trillion, three hundred twenty-four billion, four hundred three million, three hundred twelve thousand, four hundred eighty-seven".