Base | Representation |
---|---|
bin | 1000010101101000110… |
… | …1111001001000100101 |
3 | 111200202011110120212011 |
4 | 2011122031321020211 |
5 | 4321332330341401 |
6 | 145450151154221 |
7 | 13230543522421 |
oct | 2053215711045 |
9 | 450664416764 |
10 | 143247512101 |
11 | 55829539041 |
12 | 23919375971 |
13 | 1067b6276a5 |
14 | 6d0ca63b81 |
15 | 3ad5da7451 |
hex | 215a379225 |
143247512101 has 2 divisors, whose sum is σ = 143247512102. Its totient is φ = 143247512100.
The previous prime is 143247512087. The next prime is 143247512153. The reversal of 143247512101 is 101215742341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 135590387076 + 7657125025 = 368226^2 + 87505^2 .
It is a cyclic number.
It is not a de Polignac number, because 143247512101 - 229 = 142710641189 is a prime.
It is a super-3 number, since 3×1432475121013 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (143247552101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71623756050 + 71623756051.
It is an arithmetic number, because the mean of its divisors is an integer number (71623756051).
Almost surely, 2143247512101 is an apocalyptic number.
It is an amenable number.
143247512101 is a deficient number, since it is larger than the sum of its proper divisors (1).
143247512101 is an equidigital number, since it uses as much as digits as its factorization.
143247512101 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6720, while the sum is 31.
The spelling of 143247512101 in words is "one hundred forty-three billion, two hundred forty-seven million, five hundred twelve thousand, one hundred one".
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