Base | Representation |
---|---|
bin | 11010101011101011… |
… | …00101101011101111 |
3 | 1100222100001001220121 |
4 | 31111311211223233 |
5 | 213314200410411 |
6 | 10325242425411 |
7 | 1014662413654 |
oct | 152565455357 |
9 | 40870031817 |
10 | 14325013231 |
11 | 6091107511 |
12 | 2939502267 |
13 | 1473a56bb9 |
14 | 99c71bc2b |
15 | 58c933571 |
hex | 355d65aef |
14325013231 has 4 divisors (see below), whose sum is σ = 14787110464. Its totient is φ = 13862916000.
The previous prime is 14325013223. The next prime is 14325013237. The reversal of 14325013231 is 13231052341.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14325013231 - 23 = 14325013223 is a prime.
It is a super-2 number, since 2×143250132312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14325013196 and 14325013205.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14325013237) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 231048570 + ... + 231048631.
It is an arithmetic number, because the mean of its divisors is an integer number (3696777616).
Almost surely, 214325013231 is an apocalyptic number.
14325013231 is a deficient number, since it is larger than the sum of its proper divisors (462097233).
14325013231 is an equidigital number, since it uses as much as digits as its factorization.
14325013231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 462097232.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 14325013231 its reverse (13231052341), we get a palindrome (27556065572).
The spelling of 14325013231 in words is "fourteen billion, three hundred twenty-five million, thirteen thousand, two hundred thirty-one".
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