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143253311040 = 263257267109139
BaseRepresentation
bin1000010101101010010…
…0000000111001000000
3111200202120101012111200
42011122210000321000
54321340321423130
6145450515341200
713230644024100
oct2053244007100
9450676335450
10143253311040
1155831839954
122391b2b1800
131067c8a8008
146d0d733200
153ad6650760
hex215a900e40

143253311040 has 1008 divisors, whose sum is σ = 591293102400. Its totient is φ = 31729065984.

The previous prime is 143253311027. The next prime is 143253311053. The reversal of 143253311040 is 40113352341.

It is a happy number.

143253311040 is a `hidden beast` number, since 1 + 4 + 325 + 331 + 1 + 0 + 4 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (143253311027) and next prime (143253311053).

It is a tau number, because it is divible by the number of its divisors (1008).

It is a super-2 number, since 2×1432533110402 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 143253310995 and 143253311013.

It is an unprimeable number.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 1030599291 + ... + 1030599429.

It is an arithmetic number, because the mean of its divisors is an integer number (586600300).

Almost surely, 2143253311040 is an apocalyptic number.

143253311040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 143253311040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (295646551200).

143253311040 is an abundant number, since it is smaller than the sum of its proper divisors (448039791360).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

143253311040 is a wasteful number, since it uses less digits than its factorization.

143253311040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 352 (or 332 counting only the distinct ones).

The product of its (nonzero) digits is 4320, while the sum is 27.

Adding to 143253311040 its reverse (40113352341), we get a palindrome (183366663381).

The spelling of 143253311040 in words is "one hundred forty-three billion, two hundred fifty-three million, three hundred eleven thousand, forty".