Base | Representation |
---|---|
bin | 1101000001110110110101… |
… | …1100100011010011100111 |
3 | 1212201111202100200211212221 |
4 | 3100131231130203103213 |
5 | 3334202212321231401 |
6 | 50245022351053211 |
7 | 3005662352002504 |
oct | 320355534432347 |
9 | 55644670624787 |
10 | 14325552133351 |
11 | 4623483792968 |
12 | 173447a511207 |
13 | 7cbb807c5594 |
14 | 3775090004ab |
15 | 19c9919947a1 |
hex | d076d7234e7 |
14325552133351 has 2 divisors, whose sum is σ = 14325552133352. Its totient is φ = 14325552133350.
The previous prime is 14325552133339. The next prime is 14325552133379. The reversal of 14325552133351 is 15333125552341.
It is a weak prime.
It is an emirp because it is prime and its reverse (15333125552341) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14325552133351 - 27 = 14325552133223 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14325552133298 and 14325552133307.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14325552133051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7162776066675 + 7162776066676.
It is an arithmetic number, because the mean of its divisors is an integer number (7162776066676).
Almost surely, 214325552133351 is an apocalyptic number.
14325552133351 is a deficient number, since it is larger than the sum of its proper divisors (1).
14325552133351 is an equidigital number, since it uses as much as digits as its factorization.
14325552133351 is an evil number, because the sum of its binary digits is even.
The product of its digits is 810000, while the sum is 43.
Adding to 14325552133351 its reverse (15333125552341), we get a palindrome (29658677685692).
The spelling of 14325552133351 in words is "fourteen trillion, three hundred twenty-five billion, five hundred fifty-two million, one hundred thirty-three thousand, three hundred fifty-one".
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