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14325552133351 is a prime number
BaseRepresentation
bin1101000001110110110101…
…1100100011010011100111
31212201111202100200211212221
43100131231130203103213
53334202212321231401
650245022351053211
73005662352002504
oct320355534432347
955644670624787
1014325552133351
114623483792968
12173447a511207
137cbb807c5594
143775090004ab
1519c9919947a1
hexd076d7234e7

14325552133351 has 2 divisors, whose sum is σ = 14325552133352. Its totient is φ = 14325552133350.

The previous prime is 14325552133339. The next prime is 14325552133379. The reversal of 14325552133351 is 15333125552341.

It is a weak prime.

It is an emirp because it is prime and its reverse (15333125552341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14325552133351 - 27 = 14325552133223 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14325552133298 and 14325552133307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14325552133051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7162776066675 + 7162776066676.

It is an arithmetic number, because the mean of its divisors is an integer number (7162776066676).

Almost surely, 214325552133351 is an apocalyptic number.

14325552133351 is a deficient number, since it is larger than the sum of its proper divisors (1).

14325552133351 is an equidigital number, since it uses as much as digits as its factorization.

14325552133351 is an evil number, because the sum of its binary digits is even.

The product of its digits is 810000, while the sum is 43.

Adding to 14325552133351 its reverse (15333125552341), we get a palindrome (29658677685692).

The spelling of 14325552133351 in words is "fourteen trillion, three hundred twenty-five billion, five hundred fifty-two million, one hundred thirty-three thousand, three hundred fifty-one".