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14330023202203 is a prime number
BaseRepresentation
bin1101000010000111011111…
…1100010100110110011011
31212201221021221210200022121
43100201313330110312123
53334240341414432303
650251042145402111
73006211222315612
oct320416774246633
955657257720277
1014330023202203
114625368573095
121735307939337
137cc413bac757
14377810b38879
1519cb5426a9bd
hexd0877f14d9b

14330023202203 has 2 divisors, whose sum is σ = 14330023202204. Its totient is φ = 14330023202202.

The previous prime is 14330023202179. The next prime is 14330023202221. The reversal of 14330023202203 is 30220232003341.

It is a strong prime.

It is an emirp because it is prime and its reverse (30220232003341) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14330023202203 is a prime.

It is not a weakly prime, because it can be changed into another prime (14330023202233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7165011601101 + 7165011601102.

It is an arithmetic number, because the mean of its divisors is an integer number (7165011601102).

Almost surely, 214330023202203 is an apocalyptic number.

14330023202203 is a deficient number, since it is larger than the sum of its proper divisors (1).

14330023202203 is an equidigital number, since it uses as much as digits as its factorization.

14330023202203 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 25.

Adding to 14330023202203 its reverse (30220232003341), we get a palindrome (44550255205544).

The spelling of 14330023202203 in words is "fourteen trillion, three hundred thirty billion, twenty-three million, two hundred two thousand, two hundred three".