Base | Representation |
---|---|
bin | 1101000010001011100101… |
… | …1100010101101100111101 |
3 | 1212202001010112121011000010 |
4 | 3100202321130111230331 |
5 | 3334300114230111331 |
6 | 50251343203053433 |
7 | 3006250365025305 |
oct | 320427134255475 |
9 | 55661115534003 |
10 | 14331122113341 |
11 | 4625881904310 |
12 | 1735573971279 |
13 | 7cc55a76b927 |
14 | 3778b6a72605 |
15 | 19cbba988e46 |
hex | d08b9715b3d |
14331122113341 has 16 divisors (see below), whose sum is σ = 20858321371968. Its totient is φ = 8680089868800.
The previous prime is 14331122113339. The next prime is 14331122113361.
It is a happy number.
14331122113341 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 14331122113341 - 21 = 14331122113339 is a prime.
It is a super-2 number, since 2×143311221133412 (a number of 27 digits) contains 22 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 14331122113299 and 14331122113308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14331122113361) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 135913620 + ... + 136019021.
It is an arithmetic number, because the mean of its divisors is an integer number (1303645085748).
Almost surely, 214331122113341 is an apocalyptic number.
14331122113341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
14331122113341 is a deficient number, since it is larger than the sum of its proper divisors (6527199258627).
14331122113341 is a wasteful number, since it uses less digits than its factorization.
14331122113341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 271934252.
The product of its digits is 5184, while the sum is 30.
It can be divided in two parts, 1433112 and 2113341, that added together give a palindrome (3546453).
The spelling of 14331122113341 in words is "fourteen trillion, three hundred thirty-one billion, one hundred twenty-two million, one hundred thirteen thousand, three hundred forty-one".
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