Base | Representation |
---|---|
bin | 1000010101111000010… |
… | …1011111110100010101 |
3 | 111200220200121020220202 |
4 | 2011132011133310111 |
5 | 4322000434420432 |
6 | 145500430310245 |
7 | 13232262320546 |
oct | 2053605376425 |
9 | 450820536822 |
10 | 143312420117 |
11 | 55862141429 |
12 | 23937058385 |
13 | 1068bc025b9 |
14 | 6d1751c4cd |
15 | 3adb929462 |
hex | 215e15fd15 |
143312420117 has 2 divisors, whose sum is σ = 143312420118. Its totient is φ = 143312420116.
The previous prime is 143312420113. The next prime is 143312420201. The reversal of 143312420117 is 711024213341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 128891052196 + 14421367921 = 359014^2 + 120089^2 .
It is a cyclic number.
It is not a de Polignac number, because 143312420117 - 22 = 143312420113 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 143312420117.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (143312420113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71656210058 + 71656210059.
It is an arithmetic number, because the mean of its divisors is an integer number (71656210059).
Almost surely, 2143312420117 is an apocalyptic number.
It is an amenable number.
143312420117 is a deficient number, since it is larger than the sum of its proper divisors (1).
143312420117 is an equidigital number, since it uses as much as digits as its factorization.
143312420117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 29.
Adding to 143312420117 its reverse (711024213341), we get a palindrome (854336633458).
The spelling of 143312420117 in words is "one hundred forty-three billion, three hundred twelve million, four hundred twenty thousand, one hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.250 sec. • engine limits •