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143314154153 is a prime number
BaseRepresentation
bin1000010101111000110…
…0000111001010101001
3111200220210212100120022
42011132030013022221
54322001410413103
6145500531410225
713232313132212
oct2053614071251
9450823770508
10143314154153
1155863116215
1223937753975
131068c38b961
146d17850409
153adbb6d138
hex215e3072a9

143314154153 has 2 divisors, whose sum is σ = 143314154154. Its totient is φ = 143314154152.

The previous prime is 143314154147. The next prime is 143314154173. The reversal of 143314154153 is 351451413341.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 139105129024 + 4209025129 = 372968^2 + 64877^2 .

It is a cyclic number.

It is not a de Polignac number, because 143314154153 - 26 = 143314154089 is a prime.

It is not a weakly prime, because it can be changed into another prime (143314154173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71657077076 + 71657077077.

It is an arithmetic number, because the mean of its divisors is an integer number (71657077077).

Almost surely, 2143314154153 is an apocalyptic number.

It is an amenable number.

143314154153 is a deficient number, since it is larger than the sum of its proper divisors (1).

143314154153 is an equidigital number, since it uses as much as digits as its factorization.

143314154153 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 43200, while the sum is 35.

Adding to 143314154153 its reverse (351451413341), we get a palindrome (494765567494).

The spelling of 143314154153 in words is "one hundred forty-three billion, three hundred fourteen million, one hundred fifty-four thousand, one hundred fifty-three".