Base | Representation |
---|---|
bin | 1101000010001110111111… |
… | …0000010010010100001000 |
3 | 1212202010111001011211120220 |
4 | 3100203233300102110020 |
5 | 3334304001011441013 |
6 | 50252013433150040 |
7 | 3006312101055216 |
oct | 320435760222410 |
9 | 55663431154526 |
10 | 14332033312008 |
11 | 46261aa195365 |
12 | 1735788b5b320 |
13 | 7cc674486639 |
14 | 377961aa5cb6 |
15 | 19cc20978b23 |
hex | d08efc12508 |
14332033312008 has 16 divisors (see below), whose sum is σ = 35830083280080. Its totient is φ = 4777344437328.
The previous prime is 14332033312007. The next prime is 14332033312039. The reversal of 14332033312008 is 80021333023341.
It is a self number, because there is not a number n which added to its sum of digits gives 14332033312008.
It is not an unprimeable number, because it can be changed into a prime (14332033312007) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 298584027310 + ... + 298584027357.
It is an arithmetic number, because the mean of its divisors is an integer number (2239380205005).
Almost surely, 214332033312008 is an apocalyptic number.
It is an amenable number.
14332033312008 is an abundant number, since it is smaller than the sum of its proper divisors (21498049968072).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14332033312008 is a wasteful number, since it uses less digits than its factorization.
14332033312008 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 597168054676 (or 597168054672 counting only the distinct ones).
The product of its (nonzero) digits is 31104, while the sum is 33.
Adding to 14332033312008 its reverse (80021333023341), we get a palindrome (94353366335349).
The spelling of 14332033312008 in words is "fourteen trillion, three hundred thirty-two billion, thirty-three million, three hundred twelve thousand, eight".
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