Base | Representation |
---|---|
bin | 1101000010001110111111… |
… | …0000010010010100000111 |
3 | 1212202010111001011211120212 |
4 | 3100203233300102110013 |
5 | 3334304001011441012 |
6 | 50252013433150035 |
7 | 3006312101055215 |
oct | 320435760222407 |
9 | 55663431154525 |
10 | 14332033312007 |
11 | 46261aa195364 |
12 | 1735788b5b31b |
13 | 7cc674486638 |
14 | 377961aa5cb5 |
15 | 19cc20978b22 |
hex | d08efc12507 |
14332033312007 has 2 divisors, whose sum is σ = 14332033312008. Its totient is φ = 14332033312006.
The previous prime is 14332033311991. The next prime is 14332033312039. The reversal of 14332033312007 is 70021333023341.
It is an a-pointer prime, because the next prime (14332033312039) can be obtained adding 14332033312007 to its sum of digits (32).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14332033312007 - 24 = 14332033311991 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14332033312607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7166016656003 + 7166016656004.
It is an arithmetic number, because the mean of its divisors is an integer number (7166016656004).
Almost surely, 214332033312007 is an apocalyptic number.
14332033312007 is a deficient number, since it is larger than the sum of its proper divisors (1).
14332033312007 is an equidigital number, since it uses as much as digits as its factorization.
14332033312007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27216, while the sum is 32.
Adding to 14332033312007 its reverse (70021333023341), we get a palindrome (84353366335348).
The spelling of 14332033312007 in words is "fourteen trillion, three hundred thirty-two billion, thirty-three million, three hundred twelve thousand, seven".
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