Base | Representation |
---|---|
bin | 100000100101100101100001… |
… | …100010011100110110010010 |
3 | 200210110022000002212101012010 |
4 | 200211211201202130312102 |
5 | 122241130134412334414 |
6 | 1224452252145043350 |
7 | 42121362056450610 |
oct | 4045454142346622 |
9 | 623408002771163 |
10 | 143320400121234 |
11 | 41736927571246 |
12 | 140a8554026556 |
13 | 61c80955cb64b |
14 | 2756a5c8046b0 |
15 | 118815c344959 |
hex | 82596189cd92 |
143320400121234 has 32 divisors (see below), whose sum is σ = 327643075566720. Its totient is φ = 40941987052032.
The previous prime is 143320400121221. The next prime is 143320400121253. The reversal of 143320400121234 is 432121004023341.
It is a super-2 number, since 2×1433204001212342 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 278852569 + ... + 279366060.
It is an arithmetic number, because the mean of its divisors is an integer number (10238846111460).
Almost surely, 2143320400121234 is an apocalyptic number.
143320400121234 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
143320400121234 is an abundant number, since it is smaller than the sum of its proper divisors (184322675445486).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
143320400121234 is a wasteful number, since it uses less digits than its factorization.
143320400121234 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 558224754.
The product of its (nonzero) digits is 13824, while the sum is 30.
Adding to 143320400121234 its reverse (432121004023341), we get a palindrome (575441404144575).
The spelling of 143320400121234 in words is "one hundred forty-three trillion, three hundred twenty billion, four hundred million, one hundred twenty-one thousand, two hundred thirty-four".
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