Base | Representation |
---|---|
bin | 1000010101111010011… |
… | …1001001011101010111 |
3 | 111200221022012102111002 |
4 | 2011132213021131113 |
5 | 4322010214211211 |
6 | 145501343333515 |
7 | 13232430310634 |
oct | 2053647113527 |
9 | 450838172432 |
10 | 143321241431 |
11 | 55867116a75 |
12 | 23939bb129b |
13 | 106909a0804 |
14 | 6d1877718b |
15 | 3adc5bd03b |
hex | 215e9c9757 |
143321241431 has 2 divisors, whose sum is σ = 143321241432. Its totient is φ = 143321241430.
The previous prime is 143321241419. The next prime is 143321241439. The reversal of 143321241431 is 134142123341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 143321241431 - 210 = 143321240407 is a prime.
It is a super-2 number, since 2×1433212414312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 143321241394 and 143321241403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (143321241439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71660620715 + 71660620716.
It is an arithmetic number, because the mean of its divisors is an integer number (71660620716).
Almost surely, 2143321241431 is an apocalyptic number.
143321241431 is a deficient number, since it is larger than the sum of its proper divisors (1).
143321241431 is an equidigital number, since it uses as much as digits as its factorization.
143321241431 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6912, while the sum is 29.
Adding to 143321241431 its reverse (134142123341), we get a palindrome (277463364772).
The spelling of 143321241431 in words is "one hundred forty-three billion, three hundred twenty-one million, two hundred forty-one thousand, four hundred thirty-one".
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